The minimum fee is for the transaction as a whole, calculated as a * size(tx) + b, where a and b are protocol parameters. However, there is a Min-Ada-Value of 1 ADA which is the minimum size of a UTxO. The entire UTxO set of Cardano is actually 45 billion for this reason. Anyway, you'd need to send 1 ADA per UTxO (which can be in the same transaction) and then the only limit should be the size of the transaction being less than the size limit of a block.

You can read more about this here:

Docs: https://cardano-ledger.readthedocs.io/en/latest/explanations/min-utxo.html

Implementation: https://github.com/input-output-hk/cardano-ledger-specs/blob/master/shelley-ma/impl/src/Cardano/Ledger/ShelleyMA/Rules/Utxo.hs

The minimum fee is for the transaction as a whole, calculated as a * size(tx) + b, where a and b are protocol parameters. However, there is a Min-Ada-Value of 1 ADA which is the minimum size of a UTxO. The maximum possible UTxO set of Cardano is actually 45 billion for this reason. Anyway, you'd need to send 1 ADA per UTxO (which can be in the same transaction) and then the only limit should be the size of the transaction being less than the size limit of a block.

You can read more about this here:

Docs: https://cardano-ledger.readthedocs.io/en/latest/explanations/min-utxo.html

Implementation: https://github.com/input-output-hk/cardano-ledger-specs/blob/master/shelley-ma/impl/src/Cardano/Ledger/ShelleyMA/Rules/Utxo.hs